Shooting Gallery

Shooting Gallery
Shooting Gallery

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Hunter Series Beast or Buddy Rapid Fire Shooting Gallery Toy Gun Game


Hunter Series Beast or Buddy Rapid Fire Shooting Gallery
Toy Gun Game


$24.95


Hunter Series Beast or Buddy Rapid Fire Shooting Gallery Toy Gun Game


Hunter Series Beast or Buddy Rapid Fire Shooting Gallery Toy Gun Game


$24.95


NEW Hunter Series Shooting Gallery Game TOY !


NEW Hunter Series Shooting Gallery
Game Toy !


$19.99


Hunter Series Beast or Buddy Rapid Fire Shooting Gallery Toy Gun Game


Hunter Series Beast or Buddy Rapid Fire Shooting Gallery Toy Gun Game


$24.95


Hunter Series Beast or Buddy Rapid Fire Shooting Gallery Toy Gun Game


Hunter Series Beast or Buddy Rapid Fire Shooting Gallery Toy Gun Game


$24.95


Vintage Plastic Electronic Shooting Gallery or Game Toy Gun/Pistol 11


Vintage Plastic Electronic Shooting Gallery or Game Toy Gun/Pistol 11″


$9.99


Ideal Electro shot Shooting Gallery  High Speed Shooter NIB


Ideal Electro shot Shooting Gallery
High Speed Shooter NIB


$39.95


Ideal Industries Electro Shot Shooting Gallery


Ideal Industries Electro Shot Shooting Gallery


$69.95


Old School Magic Shot Shooting Gallery


Old School Magic Shot Shooting Gallery


$4.99


Electro Shot Shooting Gallery


Electro Shot Shooting Gallery


$49.99


1977 Hasbro Lite Blaster Shooting Gallery Red Baron Target Airplanes MIB Scarce


1977 Hasbro Lite Blaster Shooting Gallery Red Baron Target Airplanes MIB Scarce


$99.00


Learn to Draw Shooting Gallery Gun Set


Learn to Draw Shooting Gallery Gun Set


$39.99


Suppose we fire a rifle bullet (1650 m / s) in a shooting gallery and listen to the gong in the white collar 0.813 s?

Suppose a fire rifle bullet (1650 m / s) in a shooting gallery and listen to the gong in the lens ring of 0,813 s later. Taking the speed of sound 330 m / s, and assuming the bullet travels directly toward the ground at a constant speed, the distance is the objective? ______m Please, please explain the process and show their work. Thanks in advance! n Juan golfmaniac r so wrong: (Thanks Paul!

I beg you not to listen to others who have responded. The first is to play with you and the second is through equation wrong and not know what he's talking about. Here's the deal, this will take a few steps. First, realize that it is necessary to break this down into two equations both the D = RT (distance = velocity * time.) The first equation deals with the bullet goes down, the second deals with the sound to return. 1) Downloading: D1 = D1 T1 R1 * is unknown, T1 is unknown, all we know is R1 = 1650 2) comes back: R2 D2 = D2 * T2 is unknown, T2 is unknown, all we know is R2 = 330 This is a real problem, because we have two equations and unknowns 4. The key is to realize two things: a) The D's are the same. The uprange distance is exactly the same as the distance to the ground. Therefore, eliminating the D2 and D1, instead just use D for both. b) You know one more piece of information: T1 + T2 = 0.813 Now you have 3 equations, 3 unknowns, and we can solve for each variable. T2 = 0813 – T1 (using the equation of a second) D = 330 (0813 – T1) = 268.29 to 330 * T1 equation Now put 1 and 2 equal to each other, giving: 268.29 to 330 * 1650 * T1 T1 = T1 to solve by adding 330 to both sides and dividing both sides by 1650, receiving: T1 = 0.1355 Plug this into the original equation of the first to find the distance: D = 1650 *. 1355 D = 223,575 m can prove that this is correct, finding T2 (T1 and know the equation that relates T1 to T2), then plug that into the second equation. You will find that the D is the same, as it should, so you know you've made the right problem. Hope this helps

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