Heli Force
Hey, it's a physics problem:) help please?
An attack helicopter is equipped with a 20 mm cannon that fires projectiles 88.6 g in the forward direction with a muzzle velocity of 382 m / s. fully loaded helicopter has a mass of 332 kg. An explosion of shells of 74.1 shoots within a range 3.29 s. A) What is the average of the resultant force on the helicopter? I got it, F = m (v / t), then F x number of bullets fired. B) How how much is the feed rate reduced? Answer in m / s. .. Hm that's one I'm having some problems. i use kinetic energy conserved? Momentum conserved? bah .. someone please help:)
Setback in common everyday language, is considered the backward kick or force produced by a gun when shooting. In terms scientists more precise, this force is equal to the derivative of the backward momentum resulting when a gun is fired. The backward movement is equal to the mass of gun times its reverse rate. This backward momentum is equal to the sum of the two momentums submitted by the law of conservation of momentum and should be and equals mass times its the projectile velocity adds to the mass of exhaust gas, fuel burned, unburned fuel, and other gases, the time of their velocity. For if we do not know sufficient information on the gases and other byproducts of cooking. However, if we assume they are negligible, we can focus on the cartoons. Conservation quantity Motion: MH * MH * VH1 = VH2 + vb * where Mb, Mh is the mass of the helicopter VH1 is the initial velocity of the helicopter VH2 is the speed of the helicopter after of Mb is the mass firing of bullets vb is the velocity of bullets depending on the accuracy of the answer you want, you may want to consider that the mass of the helicopter change as the bullets leave the gun. Mh * VH1 = (Mh – Mb) * Mb + vb VH2 however, did not have enough information to rule on this case. Do you need know the speed of the helicopter after cooking (VH2). Do not worry about that, I'm probably just confusing you. Back to the question: Mh = Mh * * VH1 VH2 Vb + Mb * Mh * VH1 – VH2 Mb * Mh = Mh * * vb (VH1 – VH2) Mb * vb = (VH1 – VH2) Mb = vb * / Mh
